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100111221002017 is a prime number
BaseRepresentation
bin10110110000110011110101…
…110001000000111100100001
3111010110112120010020211112201
4112300303311301000330201
5101110210240034031032
6552530243210453201
730041540245102321
oct2660636561007441
9433415503224481
10100111221002017
1129997a263a8165
12b28a285434201
1343b25a85ab844
141aa15a2231281
15b891c8ba08e7
hex5b0cf5c40f21

100111221002017 has 2 divisors, whose sum is σ = 100111221002018. Its totient is φ = 100111221002016.

The previous prime is 100111221001951. The next prime is 100111221002033. The reversal of 100111221002017 is 710200122111001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57514765654801 + 42596455347216 = 7583849^2 + 6526596^2 .

It is a cyclic number.

It is not a de Polignac number, because 100111221002017 - 211 = 100111220999969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100111221001985 and 100111221002003.

It is not a weakly prime, because it can be changed into another prime (100111224002017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055610501008 + 50055610501009.

It is an arithmetic number, because the mean of its divisors is an integer number (50055610501009).

Almost surely, 2100111221002017 is an apocalyptic number.

It is an amenable number.

100111221002017 is a deficient number, since it is larger than the sum of its proper divisors (1).

100111221002017 is an equidigital number, since it uses as much as digits as its factorization.

100111221002017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 100111221002017 its reverse (710200122111001), we get a palindrome (810311343113018).

The spelling of 100111221002017 in words is "one hundred trillion, one hundred eleven billion, two hundred twenty-one million, two thousand, seventeen".