Base | Representation |
---|---|
bin | 10110110000110100101011… |
… | …011110001000100011001001 |
3 | 111010110121212220200101201111 |
4 | 112300310223132020203021 |
5 | 101110214111214201324 |
6 | 552530512434450321 |
7 | 30041601465460102 |
oct | 2660645336104311 |
9 | 433417786611644 |
10 | 100112122022089 |
11 | 29998348a66951 |
12 | b28a4971339a1 |
13 | 43b26c0171608 |
14 | 1aa1649b753a9 |
15 | b8922cd2e794 |
hex | 5b0d2b7888c9 |
100112122022089 has 2 divisors, whose sum is σ = 100112122022090. Its totient is φ = 100112122022088.
The previous prime is 100112122022047. The next prime is 100112122022149. The reversal of 100112122022089 is 980220221211001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 56021632257600 + 44090489764489 = 7484760^2 + 6640067^2 .
It is an emirp because it is prime and its reverse (980220221211001) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100112122022089 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 100112122022089.
It is not a weakly prime, because it can be changed into another prime (100112122022189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50056061011044 + 50056061011045.
It is an arithmetic number, because the mean of its divisors is an integer number (50056061011045).
Almost surely, 2100112122022089 is an apocalyptic number.
It is an amenable number.
100112122022089 is a deficient number, since it is larger than the sum of its proper divisors (1).
100112122022089 is an equidigital number, since it uses as much as digits as its factorization.
100112122022089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 31.
The spelling of 100112122022089 in words is "one hundred trillion, one hundred twelve billion, one hundred twenty-two million, twenty-two thousand, eighty-nine".
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