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10011311119961 is a prime number
BaseRepresentation
bin1001000110101111000010…
…1001001001111001011001
31022110001221111002200102022
42101223300221021321121
52303011131121314321
633143044405344225
72052202423312364
oct221536051117131
938401844080368
1010011311119961
11320a856150948
121158313a08075
135780a7675208
1426879b4690db
1512563ce8adab
hex91af0a49e59

10011311119961 has 2 divisors, whose sum is σ = 10011311119962. Its totient is φ = 10011311119960.

The previous prime is 10011311119919. The next prime is 10011311119967. The reversal of 10011311119961 is 16991111311001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8535951073225 + 1475360046736 = 2921635^2 + 1214644^2 .

It is a cyclic number.

It is not a de Polignac number, because 10011311119961 - 218 = 10011310857817 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (10011311119967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005655559980 + 5005655559981.

It is an arithmetic number, because the mean of its divisors is an integer number (5005655559981).

Almost surely, 210011311119961 is an apocalyptic number.

It is an amenable number.

10011311119961 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011311119961 is an equidigital number, since it uses as much as digits as its factorization.

10011311119961 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 35.

The spelling of 10011311119961 in words is "ten trillion, eleven billion, three hundred eleven million, one hundred nineteen thousand, nine hundred sixty-one".