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10011311122011 = 33337103707337
BaseRepresentation
bin1001000110101111000010…
…1001001010011001011011
31022110001221111002210020020
42101223300221022121123
52303011131121401021
633143044405401523
72052202423321353
oct221536051123133
938401844083206
1010011311122011
11320a856152441
121158313a092a3
135780a7676124
1426879b469b63
1512563ce8b7c6
hex91af0a4a65b

10011311122011 has 4 divisors (see below), whose sum is σ = 13348414829352. Its totient is φ = 6674207414672.

The previous prime is 10011311121983. The next prime is 10011311122037. The reversal of 10011311122011 is 11022111311001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10011311122011 - 217 = 10011310990939 is a prime.

It is a super-2 number, since 2×100113111220112 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (10011311122061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1668551853666 + ... + 1668551853671.

It is an arithmetic number, because the mean of its divisors is an integer number (3337103707338).

Almost surely, 210011311122011 is an apocalyptic number.

10011311122011 is a deficient number, since it is larger than the sum of its proper divisors (3337103707341).

10011311122011 is an equidigital number, since it uses as much as digits as its factorization.

10011311122011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3337103707340.

The product of its (nonzero) digits is 12, while the sum is 15.

Adding to 10011311122011 its reverse (11022111311001), we get a palindrome (21033422433012).

The spelling of 10011311122011 in words is "ten trillion, eleven billion, three hundred eleven million, one hundred twenty-two thousand, eleven".

Divisors: 1 3 3337103707337 10011311122011