Base | Representation |
---|---|
bin | 1001000110110010000110… |
… | …1000110101100111101001 |
3 | 1022110011001202211122011022 |
4 | 2101230201220311213221 |
5 | 2303014322034323424 |
6 | 33143302131542225 |
7 | 2052231664226363 |
oct | 221544150654751 |
9 | 38404052748138 |
10 | 10012133120489 |
11 | 3210138149025 |
12 | 115850315a975 |
13 | 5781a8a5bc66 |
14 | 2688386bdd33 |
15 | 12568a20b95e |
hex | 91b21a359e9 |
10012133120489 has 2 divisors, whose sum is σ = 10012133120490. Its totient is φ = 10012133120488.
The previous prime is 10012133120471. The next prime is 10012133120527. The reversal of 10012133120489 is 98402133121001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8352331201600 + 1659801918889 = 2890040^2 + 1288333^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10012133120489 is a prime.
It is not a weakly prime, because it can be changed into another prime (10012133120449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006066560244 + 5006066560245.
It is an arithmetic number, because the mean of its divisors is an integer number (5006066560245).
Almost surely, 210012133120489 is an apocalyptic number.
It is an amenable number.
10012133120489 is a deficient number, since it is larger than the sum of its proper divisors (1).
10012133120489 is an equidigital number, since it uses as much as digits as its factorization.
10012133120489 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 35.
The spelling of 10012133120489 in words is "ten trillion, twelve billion, one hundred thirty-three million, one hundred twenty thousand, four hundred eighty-nine".
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