Base | Representation |
---|---|
bin | 10110110000111110000100… |
… | …111000011001000001100011 |
3 | 111010111120221002202222222101 |
4 | 112300332010320121001203 |
5 | 101110400242233342011 |
6 | 552535301554151231 |
7 | 30042406515123511 |
oct | 2660760470310143 |
9 | 433446832688871 |
10 | 100122212012131 |
11 | 299a16565557a1 |
12 | b290432282517 |
13 | 43b363a6a931a |
14 | 1aa1d25c414b1 |
15 | b8961da662c1 |
hex | 5b0f84e19063 |
100122212012131 has 2 divisors, whose sum is σ = 100122212012132. Its totient is φ = 100122212012130.
The previous prime is 100122212012099. The next prime is 100122212012201. The reversal of 100122212012131 is 131210212221001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100122212012131 - 25 = 100122212012099 is a prime.
It is a super-2 number, since 2×1001222120121312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100122212012099 and 100122212012108.
It is not a weakly prime, because it can be changed into another prime (100122212012531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50061106006065 + 50061106006066.
It is an arithmetic number, because the mean of its divisors is an integer number (50061106006066).
Almost surely, 2100122212012131 is an apocalyptic number.
100122212012131 is a deficient number, since it is larger than the sum of its proper divisors (1).
100122212012131 is an equidigital number, since it uses as much as digits as its factorization.
100122212012131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 100122212012131 its reverse (131210212221001), we get a palindrome (231332424233132).
The spelling of 100122212012131 in words is "one hundred trillion, one hundred twenty-two billion, two hundred twelve million, twelve thousand, one hundred thirty-one".
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