Base | Representation |
---|---|
bin | 10110110000111111110000… |
… | …001111000010010010100010 |
3 | 111010111202120121212021100221 |
4 | 112300333300033002102202 |
5 | 101110412434324013214 |
6 | 552540200414033254 |
7 | 30042502245164125 |
oct | 2660776017022242 |
9 | 433452517767327 |
10 | 100124013110434 |
11 | 299a23a019a595 |
12 | b2908554a882a |
13 | 43b3866892271 |
14 | 1aa20571223bc |
15 | b896c6c39e24 |
hex | 5b0ff03c24a2 |
100124013110434 has 4 divisors (see below), whose sum is σ = 150186019665654. Its totient is φ = 50062006555216.
The previous prime is 100124013110413. The next prime is 100124013110441. The reversal of 100124013110434 is 434011310421001.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 72202458823209 + 27921554287225 = 8497203^2 + 5284085^2 .
It is a junction number, because it is equal to n+sod(n) for n = 100124013110399 and 100124013110408.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25031003277607 + ... + 25031003277610.
Almost surely, 2100124013110434 is an apocalyptic number.
100124013110434 is a deficient number, since it is larger than the sum of its proper divisors (50062006555220).
100124013110434 is an equidigital number, since it uses as much as digits as its factorization.
100124013110434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50062006555219.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 100124013110434 its reverse (434011310421001), we get a palindrome (534135323531435).
The spelling of 100124013110434 in words is "one hundred trillion, one hundred twenty-four billion, thirteen million, one hundred ten thousand, four hundred thirty-four".
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