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100124013110434 = 250062006555217
BaseRepresentation
bin10110110000111111110000…
…001111000010010010100010
3111010111202120121212021100221
4112300333300033002102202
5101110412434324013214
6552540200414033254
730042502245164125
oct2660776017022242
9433452517767327
10100124013110434
11299a23a019a595
12b2908554a882a
1343b3866892271
141aa20571223bc
15b896c6c39e24
hex5b0ff03c24a2

100124013110434 has 4 divisors (see below), whose sum is σ = 150186019665654. Its totient is φ = 50062006555216.

The previous prime is 100124013110413. The next prime is 100124013110441. The reversal of 100124013110434 is 434011310421001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 72202458823209 + 27921554287225 = 8497203^2 + 5284085^2 .

It is a junction number, because it is equal to n+sod(n) for n = 100124013110399 and 100124013110408.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25031003277607 + ... + 25031003277610.

Almost surely, 2100124013110434 is an apocalyptic number.

100124013110434 is a deficient number, since it is larger than the sum of its proper divisors (50062006555220).

100124013110434 is an equidigital number, since it uses as much as digits as its factorization.

100124013110434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50062006555219.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 100124013110434 its reverse (434011310421001), we get a palindrome (534135323531435).

The spelling of 100124013110434 in words is "one hundred trillion, one hundred twenty-four billion, thirteen million, one hundred ten thousand, four hundred thirty-four".

Divisors: 1 2 50062006555217 100124013110434