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100125433 is a prime number
BaseRepresentation
bin1011111011111…
…00101011111001
320222101220021101
411331330223321
5201113003213
613534011401
72324023612
oct575745371
9228356241
10100125433
11515777a1
1229646b61
1317988925
14d424c09
158bcbbdd
hex5f7caf9

100125433 has 2 divisors, whose sum is σ = 100125434. Its totient is φ = 100125432.

The previous prime is 100125409. The next prime is 100125449. The reversal of 100125433 is 334521001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95511529 + 4613904 = 9773^2 + 2148^2 .

It is a cyclic number.

It is not a de Polignac number, because 100125433 - 217 = 99994361 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 100125433.

It is not a weakly prime, because it can be changed into another prime (100123433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50062716 + 50062717.

It is an arithmetic number, because the mean of its divisors is an integer number (50062717).

Almost surely, 2100125433 is an apocalyptic number.

It is an amenable number.

100125433 is a deficient number, since it is larger than the sum of its proper divisors (1).

100125433 is an equidigital number, since it uses as much as digits as its factorization.

100125433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 19.

The square root of 100125433 is about 10006.2696845528. The cubic root of 100125433 is about 464.3528717461.

Adding to 100125433 its reverse (334521001), we get a palindrome (434646434).

The spelling of 100125433 in words is "one hundred million, one hundred twenty-five thousand, four hundred thirty-three".