100130110203113 has 32 divisors (see below), whose sum is σ = 105284019024000. Its totient is φ = 95102666072064.

The previous prime is 100130110203083. The next prime is 100130110203133. The reversal of 100130110203113 is 311302011031001.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100130110203113 is a prime.

It is a super-2 number, since 2×100130110203113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100130110203091 and 100130110203100.

It is not an unprimeable number, because it can be changed into a prime (100130110203133) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1639914281 + ... + 1639975337.

It is an arithmetic number, because the mean of its divisors is an integer number (3290125594500).

Almost surely, 2^{100130110203113} is an apocalyptic number.

It is an amenable number.

100130110203113 is a deficient number, since it is larger than the sum of its proper divisors (5153908820887).

100130110203113 is a wasteful number, since it uses less digits than its factorization.

100130110203113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64889.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 100130110203113 its reverse (311302011031001), we get a palindrome (411432121234114).

The spelling of 100130110203113 in words is "one hundred trillion, one hundred thirty billion, one hundred ten million, two hundred three thousand, one hundred thirteen".