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100130131213003 = 595233244972979
BaseRepresentation
bin10110110001000101011100…
…111001101111101011001011
3111010112100101000011002022101
4112301011130321233223023
5101111013002042304003
6552543051450134231
730043106665201633
oct2661053471575313
9433470330132271
10100130131213003
11299a4a4a756601
12b291a82421377
1343b430026c3b8
141aa24778b56c3
15b89933e0111d
hex5b115ce6facb

100130131213003 has 8 divisors (see below), whose sum is σ = 102021950491200. Its totient is φ = 98244801881928.

The previous prime is 100130131213001. The next prime is 100130131213027. The reversal of 100130131213003 is 300312131031001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100130131213003 - 21 = 100130131213001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100130131213001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1622455633 + ... + 1622517346.

It is an arithmetic number, because the mean of its divisors is an integer number (12752743811400).

Almost surely, 2100130131213003 is an apocalyptic number.

100130131213003 is a deficient number, since it is larger than the sum of its proper divisors (1891819278197).

100130131213003 is an equidigital number, since it uses as much as digits as its factorization.

100130131213003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3244973561.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 100130131213003 its reverse (300312131031001), we get a palindrome (400442262244004).

The spelling of 100130131213003 in words is "one hundred trillion, one hundred thirty billion, one hundred thirty-one million, two hundred thirteen thousand, three".

Divisors: 1 59 523 30857 3244972979 191453405761 1697120868017 100130131213003