100131112113 has 8 divisors (see below), whose sum is σ = 134062126176. Its totient is φ = 66477086400.

The previous prime is 100131112097. The next prime is 100131112117. The reversal of 100131112113 is 311211131001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100131112113 - 2⁴ = 100131112097 is a prime.

It is a super-2 number, since 2×100131112113² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100131112092 and 100131112101.

It is not an unprimeable number, because it can be changed into a prime (100131112117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69246243 + ... + 69247688.

It is an arithmetic number, because the mean of its divisors is an integer number (16757765772).

Almost surely, 2^100131112113 is an apocalyptic number.

It is an amenable number.

100131112113 is a deficient number, since it is larger than the sum of its proper divisors (33931014063).

100131112113 is a wasteful number, since it uses less digits than its factorization.

100131112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 138494175.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 100131112113 its reverse (311211131001), we get a palindrome (411342243114).

The spelling of 100131112113 in words is "one hundred billion, one hundred thirty-one million, one hundred twelve thousand, one hundred thirteen".