Base | Representation |
---|---|
bin | 10110110001000110011000… |
… | …100011011111010111011001 |
3 | 111010112102221202022221102122 |
4 | 112301012120203133113121 |
5 | 101111022024243340433 |
6 | 552543335040511025 |
7 | 30043143536641145 |
oct | 2661063043372731 |
9 | 433472852287378 |
10 | 100131132011993 |
11 | 299a5413675705 |
12 | b29210161b475 |
13 | 43b442c6c9154 |
14 | 1aa2530790225 |
15 | b89991bde198 |
hex | 5b11988df5d9 |
100131132011993 has 2 divisors, whose sum is σ = 100131132011994. Its totient is φ = 100131132011992.
The previous prime is 100131132011983. The next prime is 100131132012029. The reversal of 100131132011993 is 399110231131001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 95722194547984 + 4408937464009 = 9783772^2 + 2099747^2 .
It is a cyclic number.
It is not a de Polignac number, because 100131132011993 - 236 = 100062412535257 is a prime.
It is not a weakly prime, because it can be changed into another prime (100131132011983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50065566005996 + 50065566005997.
It is an arithmetic number, because the mean of its divisors is an integer number (50065566005997).
Almost surely, 2100131132011993 is an apocalyptic number.
It is an amenable number.
100131132011993 is a deficient number, since it is larger than the sum of its proper divisors (1).
100131132011993 is an equidigital number, since it uses as much as digits as its factorization.
100131132011993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4374, while the sum is 35.
Adding to 100131132011993 its reverse (399110231131001), we get a palindrome (499241363142994).
The spelling of 100131132011993 in words is "one hundred trillion, one hundred thirty-one billion, one hundred thirty-two million, eleven thousand, nine hundred ninety-three".
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