10013134035433 has 4 divisors (see below), whose sum is σ = 10025330301828. Its totient is φ = 10000937769040.

The previous prime is 10013134035389. The next prime is 10013134035467. The reversal of 10013134035433 is 33453043131001.

10013134035433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1830576528144 + 8182557507289 = 1352988^2 + 2860517^2 .

It is a cyclic number.

It is not a de Polignac number, because 10013134035433 - 2²⁵ = 10013100481001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10013134035395 and 10013134035404.

It is not an unprimeable number, because it can be changed into a prime (10013134035493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6098131966 + ... + 6098133607.

It is an arithmetic number, because the mean of its divisors is an integer number (2506332575457).

Almost surely, 2^{10013134035433} is an apocalyptic number.

It is an amenable number.

10013134035433 is a deficient number, since it is larger than the sum of its proper divisors (12196266395).

10013134035433 is an equidigital number, since it uses as much as digits as its factorization.

10013134035433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12196266394.

The product of its (nonzero) digits is 19440, while the sum is 31.

Adding to 10013134035433 its reverse (33453043131001), we get a palindrome (43466177166434).

The spelling of 10013134035433 in words is "ten trillion, thirteen billion, one hundred thirty-four million, thirty-five thousand, four hundred thirty-three".