100131531210331 has 2 divisors, whose sum is σ = 100131531210332. Its totient is φ = 100131531210330.

The previous prime is 100131531210299. The next prime is 100131531210341. The reversal of 100131531210331 is 133012135131001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100131531210331 - 2⁵ = 100131531210299 is a prime.

It is a super-2 number, since 2×100131531210331² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100131531210296 and 100131531210305.

It is not a weakly prime, because it can be changed into another prime (100131531210341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50065765605165 + 50065765605166.

It is an arithmetic number, because the mean of its divisors is an integer number (50065765605166).

Almost surely, 2^{100131531210331} is an apocalyptic number.

100131531210331 is a deficient number, since it is larger than the sum of its proper divisors (1).

100131531210331 is an equidigital number, since it uses as much as digits as its factorization.

100131531210331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 810, while the sum is 25.

Adding to 100131531210331 its reverse (133012135131001), we get a palindrome (233143666341332).

The spelling of 100131531210331 in words is "one hundred trillion, one hundred thirty-one billion, five hundred thirty-one million, two hundred ten thousand, three hundred thirty-one".