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10013301044849 is a prime number
BaseRepresentation
bin1001000110110110011101…
…0000000111011001110001
31022110021002011111100012002
42101231213100013121301
52303024220031413344
633144014052343345
72052302635352564
oct221554720073161
938407064440162
1010013301044849
113210687436973
12115878a314b55
13578333a0276b
142689098604db
15125707a0d44e
hex91b67407671

10013301044849 has 2 divisors, whose sum is σ = 10013301044850. Its totient is φ = 10013301044848.

The previous prime is 10013301044843. The next prime is 10013301044861. The reversal of 10013301044849 is 94844010331001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9963921538624 + 49379506225 = 3156568^2 + 222215^2 .

It is a cyclic number.

It is not a de Polignac number, because 10013301044849 - 212 = 10013301040753 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (10013301044843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006650522424 + 5006650522425.

It is an arithmetic number, because the mean of its divisors is an integer number (5006650522425).

Almost surely, 210013301044849 is an apocalyptic number.

It is an amenable number.

10013301044849 is a deficient number, since it is larger than the sum of its proper divisors (1).

10013301044849 is an equidigital number, since it uses as much as digits as its factorization.

10013301044849 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 10013301044849 in words is "ten trillion, thirteen billion, three hundred one million, forty-four thousand, eight hundred forty-nine".