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1001332300147 is a prime number
BaseRepresentation
bin11101001001001000000…
…11100101100101110011
310112201121120101021200221
432210210003211211303
5112401212032101042
62044001122153511
7132225643055014
oct16444403454563
93481546337627
101001332300147
11356731a847a3
121420941b2897
137356b30271a
143667137500b
151b0a86d6d67
hexe9240e5973

1001332300147 has 2 divisors, whose sum is σ = 1001332300148. Its totient is φ = 1001332300146.

The previous prime is 1001332300141. The next prime is 1001332300229. The reversal of 1001332300147 is 7410032331001.

It is a weak prime.

It is an emirp because it is prime and its reverse (7410032331001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1001332300147 - 227 = 1001198082419 is a prime.

It is not a weakly prime, because it can be changed into another prime (1001332300141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500666150073 + 500666150074.

It is an arithmetic number, because the mean of its divisors is an integer number (500666150074).

Almost surely, 21001332300147 is an apocalyptic number.

1001332300147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001332300147 is an equidigital number, since it uses as much as digits as its factorization.

1001332300147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 1001332300147 its reverse (7410032331001), we get a palindrome (8411364631148).

The spelling of 1001332300147 in words is "one trillion, one billion, three hundred thirty-two million, three hundred thousand, one hundred forty-seven".