100134113 has 4 divisors (see below), whose sum is σ = 101628720. Its totient is φ = 98639508.

The previous prime is 100134107. The next prime is 100134121. The reversal of 100134113 is 311431001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311431001 = 7 ⋅44490143.

It is a cyclic number.

It is not a de Polignac number, because 100134113 - 2¹⁴ = 100117729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100134613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 747203 + ... + 747336.

It is an arithmetic number, because the mean of its divisors is an integer number (25407180).

Almost surely, 2^100134113 is an apocalyptic number.

It is an amenable number.

100134113 is a deficient number, since it is larger than the sum of its proper divisors (1494607).

100134113 is an equidigital number, since it uses as much as digits as its factorization.

100134113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1494606.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 100134113 is about 10006.7034032193. The cubic root of 100134113 is about 464.3662898036.

Adding to 100134113 its reverse (311431001), we get a palindrome (411565114).

The spelling of 100134113 in words is "one hundred million, one hundred thirty-four thousand, one hundred thirteen".