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10014123201 = 33338041067
BaseRepresentation
bin10010101001110001…
…10110010011000001
3221211220100011111220
421110320312103001
5131002103420301
64333405225253
7503105433315
oct112470662301
927756304456
1010014123201
114279790a85
121b35862229
13c378c39b4
146add9bb45
153d924c936
hex254e364c1

10014123201 has 4 divisors (see below), whose sum is σ = 13352164272. Its totient is φ = 6676082132.

The previous prime is 10014123193. The next prime is 10014123209. The reversal of 10014123201 is 10232141001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (10014123193) and next prime (10014123209).

It is a cyclic number.

It is not a de Polignac number, because 10014123201 - 23 = 10014123193 is a prime.

It is not an unprimeable number, because it can be changed into a prime (10014123209) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1669020531 + ... + 1669020536.

It is an arithmetic number, because the mean of its divisors is an integer number (3338041068).

Almost surely, 210014123201 is an apocalyptic number.

It is an amenable number.

10014123201 is a deficient number, since it is larger than the sum of its proper divisors (3338041071).

10014123201 is an equidigital number, since it uses as much as digits as its factorization.

10014123201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3338041070.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 10014123201 its reverse (10232141001), we get a palindrome (20246264202).

The spelling of 10014123201 in words is "ten billion, fourteen million, one hundred twenty-three thousand, two hundred one".

Divisors: 1 3 3338041067 10014123201