100142113131033 has 8 divisors (see below), whose sum is σ = 136042115951808. Its totient is φ = 65501759532144.

The previous prime is 100142113131031. The next prime is 100142113131059. The reversal of 100142113131033 is 330131311241001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100142113131033 - 2¹ = 100142113131031 is a prime.

It is a super-2 number, since 2×100142113131033² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100142113130994 and 100142113131012.

It is not an unprimeable number, because it can be changed into a prime (100142113131031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 314912305285 + ... + 314912305602.

It is an arithmetic number, because the mean of its divisors is an integer number (17005264493976).

Almost surely, 2^{100142113131033} is an apocalyptic number.

It is an amenable number.

100142113131033 is a deficient number, since it is larger than the sum of its proper divisors (35900002820775).

100142113131033 is an equidigital number, since it uses as much as digits as its factorization.

100142113131033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 629824610943.

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 100142113131033 its reverse (330131311241001), we get a palindrome (430273424372034).

The spelling of 100142113131033 in words is "one hundred trillion, one hundred forty-two billion, one hundred thirteen million, one hundred thirty-one thousand, thirty-three".