100142123131 has 4 divisors (see below), whose sum is σ = 100862570200. Its totient is φ = 99421676064.

The previous prime is 100142123117. The next prime is 100142123161. The reversal of 100142123131 is 131321241001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131321241001 = 337 ⋅389677273.

It is a cyclic number.

It is not a de Polignac number, because 100142123131 - 2⁵ = 100142123099 is a prime.

It is a super-2 number, since 2×100142123131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100142123099 and 100142123108.

It is not an unprimeable number, because it can be changed into a prime (100142123161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 360223326 + ... + 360223603.

It is an arithmetic number, because the mean of its divisors is an integer number (25215642550).

Almost surely, 2^100142123131 is an apocalyptic number.

100142123131 is a deficient number, since it is larger than the sum of its proper divisors (720447069).

100142123131 is an equidigital number, since it uses as much as digits as its factorization.

100142123131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 720447068.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 100142123131 its reverse (131321241001), we get a palindrome (231463364132).

It can be divided in two parts, 10014 and 2123131, that added together give a triangular number (2133145 = T₂₀₆₅).

The spelling of 100142123131 in words is "one hundred billion, one hundred forty-two million, one hundred twenty-three thousand, one hundred thirty-one".