Base | Representation |
---|---|
bin | 10010101001110100… |
… | …00011101011000011 |
3 | 221211220221021021001 |
4 | 21110322003223003 |
5 | 131002144041011 |
6 | 4333420112431 |
7 | 503111223313 |
oct | 112472035303 |
9 | 27756837231 |
10 | 10014440131 |
11 | 4279988103 |
12 | 1b35995717 |
13 | c379a5027 |
14 | 6b0041443 |
15 | 3d92b17c1 |
hex | 254e83ac3 |
10014440131 has 2 divisors, whose sum is σ = 10014440132. Its totient is φ = 10014440130.
The previous prime is 10014440119. The next prime is 10014440159. The reversal of 10014440131 is 13104441001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10014440131 - 219 = 10013915843 is a prime.
It is a super-2 number, since 2×100144401312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10014440099 and 10014440108.
It is not a weakly prime, because it can be changed into another prime (10014440171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5007220065 + 5007220066.
It is an arithmetic number, because the mean of its divisors is an integer number (5007220066).
Almost surely, 210014440131 is an apocalyptic number.
10014440131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10014440131 is an equidigital number, since it uses as much as digits as its factorization.
10014440131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 10014440131 its reverse (13104441001), we get a palindrome (23118881132).
The spelling of 10014440131 in words is "ten billion, fourteen million, four hundred forty thousand, one hundred thirty-one".
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