Base | Representation |
---|---|
bin | 10010101001111011… |
… | …11000000100000001 |
3 | 221211222211010101221 |
4 | 21110331320010001 |
5 | 131002423104103 |
6 | 4333453355041 |
7 | 503122562614 |
oct | 112475700401 |
9 | 27758733357 |
10 | 10015441153 |
11 | 427a5011a3 |
12 | 1b36198a81 |
13 | c37c65853 |
14 | 6b022217b |
15 | 3d940d1bd |
hex | 254f78101 |
10015441153 has 2 divisors, whose sum is σ = 10015441154. Its totient is φ = 10015441152.
The previous prime is 10015441049. The next prime is 10015441159. The reversal of 10015441153 is 35114451001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6306265744 + 3709175409 = 79412^2 + 60903^2 .
It is a cyclic number.
It is not a de Polignac number, because 10015441153 - 221 = 10013344001 is a prime.
It is a super-2 number, since 2×100154411532 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10015441159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5007720576 + 5007720577.
It is an arithmetic number, because the mean of its divisors is an integer number (5007720577).
Almost surely, 210015441153 is an apocalyptic number.
It is an amenable number.
10015441153 is a deficient number, since it is larger than the sum of its proper divisors (1).
10015441153 is an equidigital number, since it uses as much as digits as its factorization.
10015441153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 10015441153 its reverse (35114451001), we get a palindrome (45129892154).
The spelling of 10015441153 in words is "ten billion, fifteen million, four hundred forty-one thousand, one hundred fifty-three".
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