100202012111107 has 2 divisors, whose sum is σ = 100202012111108. Its totient is φ = 100202012111106.

The previous prime is 100202012111101. The next prime is 100202012111153. The reversal of 100202012111107 is 701111210202001.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100202012111107 is a prime.

It is a super-3 number, since 3×100202012111107³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (100202012111101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50101006055553 + 50101006055554.

It is an arithmetic number, because the mean of its divisors is an integer number (50101006055554).

Almost surely, 2^{100202012111107} is an apocalyptic number.

100202012111107 is a deficient number, since it is larger than the sum of its proper divisors (1).

100202012111107 is an equidigital number, since it uses as much as digits as its factorization.

100202012111107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 100202012111107 its reverse (701111210202001), we get a palindrome (801313222313108).

The spelling of 100202012111107 in words is "one hundred trillion, two hundred two billion, twelve million, one hundred eleven thousand, one hundred seven".