Base | Representation |
---|---|
bin | 11101001010011010010… |
… | …11000010111010101011 |
3 | 10112210101122101211012021 |
4 | 32211031023002322223 |
5 | 112404120130334011 |
6 | 2044153403325311 |
7 | 132252020332633 |
oct | 16451513027253 |
9 | 3483348354167 |
10 | 1002022121131 |
11 | 356a56401489 |
12 | 142247220837 |
13 | 7364b1b9915 |
14 | 366d8c1d6c3 |
15 | 1b0e9048471 |
hex | e94d2c2eab |
1002022121131 has 2 divisors, whose sum is σ = 1002022121132. Its totient is φ = 1002022121130.
The previous prime is 1002022121119. The next prime is 1002022121141. The reversal of 1002022121131 is 1311212202001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1002022121131 - 27 = 1002022121003 is a prime.
It is a super-2 number, since 2×10020221211312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1002022121141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501011060565 + 501011060566.
It is an arithmetic number, because the mean of its divisors is an integer number (501011060566).
Almost surely, 21002022121131 is an apocalyptic number.
1002022121131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002022121131 is an equidigital number, since it uses as much as digits as its factorization.
1002022121131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1002022121131 its reverse (1311212202001), we get a palindrome (2313234323132).
The spelling of 1002022121131 in words is "one trillion, two billion, twenty-two million, one hundred twenty-one thousand, one hundred thirty-one".
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