Base | Representation |
---|---|
bin | 11101001010100101000… |
… | …10101011010110010011 |
3 | 10112210121220220102002121 |
4 | 32211102202223112103 |
5 | 112404311210432011 |
6 | 2044210342155111 |
7 | 132254163113515 |
oct | 16452242532623 |
9 | 3483556812077 |
10 | 1002112202131 |
11 | 356aa2238697 |
12 | 142271422a97 |
13 | 73663a696a1 |
14 | 36706b8bbb5 |
15 | 1b101ddde71 |
hex | e9528ab593 |
1002112202131 has 2 divisors, whose sum is σ = 1002112202132. Its totient is φ = 1002112202130.
The previous prime is 1002112202111. The next prime is 1002112202137. The reversal of 1002112202131 is 1312022112001.
1002112202131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (1312022112001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1002112202131 - 221 = 1002110104979 is a prime.
It is a super-2 number, since 2×10021122021312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1002112202137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501056101065 + 501056101066.
It is an arithmetic number, because the mean of its divisors is an integer number (501056101066).
Almost surely, 21002112202131 is an apocalyptic number.
1002112202131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002112202131 is an equidigital number, since it uses as much as digits as its factorization.
1002112202131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1002112202131 its reverse (1312022112001), we get a palindrome (2314134314132).
The spelling of 1002112202131 in words is "one trillion, two billion, one hundred twelve million, two hundred two thousand, one hundred thirty-one".
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