Base | Representation |
---|---|
bin | 10110110010010001110010… |
… | …101111111001101111111011 |
3 | 111010211011221200212002222221 |
4 | 112302101302233321233323 |
5 | 101113333341120011303 |
6 | 553044445411024511 |
7 | 30052041211264336 |
oct | 2662216257715773 |
9 | 433734850762887 |
10 | 100212102110203 |
11 | 29a26794131946 |
12 | b2a593a29b137 |
13 | 43bbc647cba75 |
14 | 1aa64122d161d |
15 | b8bb304344bd |
hex | 5b2472bf9bfb |
100212102110203 has 2 divisors, whose sum is σ = 100212102110204. Its totient is φ = 100212102110202.
The previous prime is 100212102110171. The next prime is 100212102110269. The reversal of 100212102110203 is 302011201212001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100212102110203 - 25 = 100212102110171 is a prime.
It is not a weakly prime, because it can be changed into another prime (100212102111203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50106051055101 + 50106051055102.
It is an arithmetic number, because the mean of its divisors is an integer number (50106051055102).
Almost surely, 2100212102110203 is an apocalyptic number.
100212102110203 is a deficient number, since it is larger than the sum of its proper divisors (1).
100212102110203 is an equidigital number, since it uses as much as digits as its factorization.
100212102110203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 100212102110203 its reverse (302011201212001), we get a palindrome (402223303322204).
The spelling of 100212102110203 in words is "one hundred trillion, two hundred twelve billion, one hundred two million, one hundred ten thousand, two hundred three".
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