Base | Representation |
---|---|
bin | 10110110010010001110011… |
… | …110100001110010010010001 |
3 | 111010211011222221120000202221 |
4 | 112302101303310032102101 |
5 | 101113333410211120423 |
6 | 553044451250541041 |
7 | 30052041516436663 |
oct | 2662216364162221 |
9 | 433734887500687 |
10 | 100212120020113 |
11 | 29a267a3254922 |
12 | b2a5944297781 |
13 | 43bbc6842ca4a |
14 | 1aa6414834533 |
15 | b8bb31cc0e5d |
hex | 5b2473d0e491 |
100212120020113 has 2 divisors, whose sum is σ = 100212120020114. Its totient is φ = 100212120020112.
The previous prime is 100212120020063. The next prime is 100212120020149. The reversal of 100212120020113 is 311020021212001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100210270418064 + 1849602049 = 10010508^2 + 43007^2 .
It is a cyclic number.
It is not a de Polignac number, because 100212120020113 - 213 = 100212120011921 is a prime.
It is not a weakly prime, because it can be changed into another prime (100212120020513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50106060010056 + 50106060010057.
It is an arithmetic number, because the mean of its divisors is an integer number (50106060010057).
Almost surely, 2100212120020113 is an apocalyptic number.
It is an amenable number.
100212120020113 is a deficient number, since it is larger than the sum of its proper divisors (1).
100212120020113 is an equidigital number, since it uses as much as digits as its factorization.
100212120020113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 100212120020113 its reverse (311020021212001), we get a palindrome (411232141232114).
The spelling of 100212120020113 in words is "one hundred trillion, two hundred twelve billion, one hundred twenty million, twenty thousand, one hundred thirteen".
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