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100212120020113 is a prime number
BaseRepresentation
bin10110110010010001110011…
…110100001110010010010001
3111010211011222221120000202221
4112302101303310032102101
5101113333410211120423
6553044451250541041
730052041516436663
oct2662216364162221
9433734887500687
10100212120020113
1129a267a3254922
12b2a5944297781
1343bbc6842ca4a
141aa6414834533
15b8bb31cc0e5d
hex5b2473d0e491

100212120020113 has 2 divisors, whose sum is σ = 100212120020114. Its totient is φ = 100212120020112.

The previous prime is 100212120020063. The next prime is 100212120020149. The reversal of 100212120020113 is 311020021212001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100210270418064 + 1849602049 = 10010508^2 + 43007^2 .

It is a cyclic number.

It is not a de Polignac number, because 100212120020113 - 213 = 100212120011921 is a prime.

It is not a weakly prime, because it can be changed into another prime (100212120020513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50106060010056 + 50106060010057.

It is an arithmetic number, because the mean of its divisors is an integer number (50106060010057).

Almost surely, 2100212120020113 is an apocalyptic number.

It is an amenable number.

100212120020113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100212120020113 is an equidigital number, since it uses as much as digits as its factorization.

100212120020113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 100212120020113 its reverse (311020021212001), we get a palindrome (411232141232114).

The spelling of 100212120020113 in words is "one hundred trillion, two hundred twelve billion, one hundred twenty million, twenty thousand, one hundred thirteen".