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10021420113 = 33340473371
BaseRepresentation
bin10010101010101001…
…01011110001010001
3221212102001212222220
421111110223301101
5131010440420423
64334225451253
7503224444155
oct112524536121
927772055886
1010021420113
114282915291
121b381a0b29
13c3927a0b3
146b0d3b065
153d9bde9e3
hex25552bc51

10021420113 has 4 divisors (see below), whose sum is σ = 13361893488. Its totient is φ = 6680946740.

The previous prime is 10021420111. The next prime is 10021420153. The reversal of 10021420113 is 31102412001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10021420113 - 21 = 10021420111 is a prime.

It is a super-2 number, since 2×100214201132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10021420092 and 10021420101.

It is not an unprimeable number, because it can be changed into a prime (10021420111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1670236683 + ... + 1670236688.

It is an arithmetic number, because the mean of its divisors is an integer number (3340473372).

Almost surely, 210021420113 is an apocalyptic number.

It is an amenable number.

10021420113 is a deficient number, since it is larger than the sum of its proper divisors (3340473375).

10021420113 is an equidigital number, since it uses as much as digits as its factorization.

10021420113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3340473374.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 10021420113 its reverse (31102412001), we get a palindrome (41123832114).

The spelling of 10021420113 in words is "ten billion, twenty-one million, four hundred twenty thousand, one hundred thirteen".

Divisors: 1 3 3340473371 10021420113