Base | Representation |
---|---|
bin | 101110101010100111… |
… | …1011100110111010001 |
3 | 100120200010000001000111 |
4 | 1131111033130313101 |
5 | 3120214334032203 |
6 | 114012101321321 |
7 | 10145256006205 |
oct | 1352517346721 |
9 | 316603001014 |
10 | 100214361553 |
11 | 39556438109 |
12 | 17509706241 |
13 | 95b10548b7 |
14 | 4bc9700b05 |
15 | 2917e7e26d |
hex | 17553dcdd1 |
100214361553 has 2 divisors, whose sum is σ = 100214361554. Its totient is φ = 100214361552.
The previous prime is 100214361517. The next prime is 100214361557. The reversal of 100214361553 is 355163412001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54603070929 + 45611290624 = 233673^2 + 213568^2 .
It is a cyclic number.
It is not a de Polignac number, because 100214361553 - 29 = 100214361041 is a prime.
It is a super-3 number, since 3×1002143615533 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (100214361557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50107180776 + 50107180777.
It is an arithmetic number, because the mean of its divisors is an integer number (50107180777).
Almost surely, 2100214361553 is an apocalyptic number.
It is an amenable number.
100214361553 is a deficient number, since it is larger than the sum of its proper divisors (1).
100214361553 is an equidigital number, since it uses as much as digits as its factorization.
100214361553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 100214361553 its reverse (355163412001), we get a palindrome (455377773554).
The spelling of 100214361553 in words is "one hundred billion, two hundred fourteen million, three hundred sixty-one thousand, five hundred fifty-three".
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