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100214361553 is a prime number
BaseRepresentation
bin101110101010100111…
…1011100110111010001
3100120200010000001000111
41131111033130313101
53120214334032203
6114012101321321
710145256006205
oct1352517346721
9316603001014
10100214361553
1139556438109
1217509706241
1395b10548b7
144bc9700b05
152917e7e26d
hex17553dcdd1

100214361553 has 2 divisors, whose sum is σ = 100214361554. Its totient is φ = 100214361552.

The previous prime is 100214361517. The next prime is 100214361557. The reversal of 100214361553 is 355163412001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 54603070929 + 45611290624 = 233673^2 + 213568^2 .

It is a cyclic number.

It is not a de Polignac number, because 100214361553 - 29 = 100214361041 is a prime.

It is a super-3 number, since 3×1002143615533 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (100214361557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50107180776 + 50107180777.

It is an arithmetic number, because the mean of its divisors is an integer number (50107180777).

Almost surely, 2100214361553 is an apocalyptic number.

It is an amenable number.

100214361553 is a deficient number, since it is larger than the sum of its proper divisors (1).

100214361553 is an equidigital number, since it uses as much as digits as its factorization.

100214361553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 100214361553 its reverse (355163412001), we get a palindrome (455377773554).

The spelling of 100214361553 in words is "one hundred billion, two hundred fourteen million, three hundred sixty-one thousand, five hundred fifty-three".