Base | Representation |
---|---|
bin | 11101001010101001111… |
… | …11111010011011001011 |
3 | 10112210201210110112001112 |
4 | 32211110333322123023 |
5 | 112404402233423431 |
6 | 2044214413440535 |
7 | 132255203344616 |
oct | 16452477723313 |
9 | 3483653415045 |
10 | 1002153420491 |
11 | 357013530653 |
12 | 1422831a014b |
13 | 7366c46b952 |
14 | 3670c43b17d |
15 | 1b105831c2b |
hex | e954ffa6cb |
1002153420491 has 2 divisors, whose sum is σ = 1002153420492. Its totient is φ = 1002153420490.
The previous prime is 1002153420487. The next prime is 1002153420517. The reversal of 1002153420491 is 1940243512001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1002153420491 - 22 = 1002153420487 is a prime.
It is a super-2 number, since 2×10021534204912 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1002153420691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501076710245 + 501076710246.
It is an arithmetic number, because the mean of its divisors is an integer number (501076710246).
Almost surely, 21002153420491 is an apocalyptic number.
1002153420491 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002153420491 is an equidigital number, since it uses as much as digits as its factorization.
1002153420491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 1002153420491 its reverse (1940243512001), we get a palindrome (2942396932492).
The spelling of 1002153420491 in words is "one trillion, two billion, one hundred fifty-three million, four hundred twenty thousand, four hundred ninety-one".
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