Base | Representation |
---|---|
bin | 111011101111000… |
… | …101010001011011 |
3 | 2120211210221100102 |
4 | 323233011101123 |
5 | 4023030314412 |
6 | 243240330015 |
7 | 33556354241 |
oct | 7357052133 |
9 | 2524727312 |
10 | 1002198107 |
11 | 4747952a9 |
12 | 23b77390b |
13 | 12c829841 |
14 | 97160791 |
15 | 5ceb78c2 |
hex | 3bbc545b |
1002198107 has 2 divisors, whose sum is σ = 1002198108. Its totient is φ = 1002198106.
The previous prime is 1002198089. The next prime is 1002198121. The reversal of 1002198107 is 7018912001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1002198107 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1002198107.
It is not a weakly prime, because it can be changed into another prime (1002198167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501099053 + 501099054.
It is an arithmetic number, because the mean of its divisors is an integer number (501099054).
Almost surely, 21002198107 is an apocalyptic number.
1002198107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002198107 is an equidigital number, since it uses as much as digits as its factorization.
1002198107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 29.
The square root of 1002198107 is about 31657.5126470795. The cubic root of 1002198107 is about 1000.7321661353.
The spelling of 1002198107 in words is "one billion, two million, one hundred ninety-eight thousand, one hundred seven".
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