Base | Representation |
---|---|
bin | 11101001010111111100… |
… | …01100100100001010011 |
3 | 10112211012101122120211010 |
4 | 32211133301210201103 |
5 | 112410240024211011 |
6 | 2044244352422003 |
7 | 132262530132252 |
oct | 16453761444123 |
9 | 3484171576733 |
10 | 1002334210131 |
11 | 3570a6592581 |
12 | 142313847903 |
13 | 7369aa5b077 |
14 | 3672845c799 |
15 | 1b1166441a6 |
hex | e95fc64853 |
1002334210131 has 8 divisors (see below), whose sum is σ = 1336708661904. Its totient is φ = 668091282560.
The previous prime is 1002334210123. The next prime is 1002334210133. The reversal of 1002334210131 is 1310124332001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1002334210131 - 23 = 1002334210123 is a prime.
It is a super-2 number, since 2×10023342101312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1002334210098 and 1002334210107.
It is not an unprimeable number, because it can be changed into a prime (1002334210133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32863266 + ... + 32893751.
It is an arithmetic number, because the mean of its divisors is an integer number (167088582738).
Almost surely, 21002334210131 is an apocalyptic number.
1002334210131 is a deficient number, since it is larger than the sum of its proper divisors (334374451773).
1002334210131 is an equidigital number, since it uses as much as digits as its factorization.
1002334210131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65762101.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1002334210131 its reverse (1310124332001), we get a palindrome (2312458542132).
The spelling of 1002334210131 in words is "one trillion, two billion, three hundred thirty-four million, two hundred ten thousand, one hundred thirty-one".
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