Base | Representation |
---|---|
bin | 10010101010111000… |
… | …00011010010001001 |
3 | 221212112201000021021 |
4 | 21111130003102021 |
5 | 131011434221213 |
6 | 4334335112441 |
7 | 503250036634 |
oct | 112534032211 |
9 | 27775630237 |
10 | 10023351433 |
11 | 4283a14317 |
12 | 1b38972721 |
13 | c397a51a4 |
14 | 6b12c0c1b |
15 | 3d9e71d8d |
hex | 255703489 |
10023351433 has 4 divisors (see below), whose sum is σ = 10052237520. Its totient is φ = 9994465348.
The previous prime is 10023351397. The next prime is 10023351439. The reversal of 10023351433 is 33415332001.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10023351433 - 221 = 10021254281 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10023351398 and 10023351407.
It is not an unprimeable number, because it can be changed into a prime (10023351439) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14442523 + ... + 14443216.
It is an arithmetic number, because the mean of its divisors is an integer number (2513059380).
Almost surely, 210023351433 is an apocalyptic number.
It is an amenable number.
10023351433 is a deficient number, since it is larger than the sum of its proper divisors (28886087).
10023351433 is an equidigital number, since it uses as much as digits as its factorization.
10023351433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28886086.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 10023351433 its reverse (33415332001), we get a palindrome (43438683434).
The spelling of 10023351433 in words is "ten billion, twenty-three million, three hundred fifty-one thousand, four hundred thirty-three".
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