100240412131 has 4 divisors (see below), whose sum is σ = 100241122392. Its totient is φ = 100239701872.

The previous prime is 100240412119. The next prime is 100240412171. The reversal of 100240412131 is 131214042001.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 100240412131 - 2⁷ = 100240412003 is a prime.

It is a super-2 number, since 2×100240412131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100240412099 and 100240412108.

It is not an unprimeable number, because it can be changed into a prime (100240412171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63730 + ... + 452263.

It is an arithmetic number, because the mean of its divisors is an integer number (25060280598).

Almost surely, 2^100240412131 is an apocalyptic number.

100240412131 is a deficient number, since it is larger than the sum of its proper divisors (710261).

100240412131 is an equidigital number, since it uses as much as digits as its factorization.

100240412131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 710260.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 100240412131 its reverse (131214042001), we get a palindrome (231454454132).

The spelling of 100240412131 in words is "one hundred billion, two hundred forty million, four hundred twelve thousand, one hundred thirty-one".