Base | Representation |
---|---|
bin | 10110110010101111100010… |
… | …100101111111100110010011 |
3 | 111010221020101201220022001011 |
4 | 112302233202211333212103 |
5 | 101114344300043110422 |
6 | 553111251110151351 |
7 | 30054251562220042 |
oct | 2662574245774623 |
9 | 433836351808034 |
10 | 100244043331987 |
11 | 29a392951165a5 |
12 | b2abb73352557 |
13 | 43c1c850cb3b9 |
14 | 1aa7ba2494559 |
15 | b8c89e6b0077 |
hex | 5b2be297f993 |
100244043331987 has 2 divisors, whose sum is σ = 100244043331988. Its totient is φ = 100244043331986.
The previous prime is 100244043331931. The next prime is 100244043332033. The reversal of 100244043331987 is 789133340442001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100244043331987 - 223 = 100244034943379 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 100244043331987.
It is not a weakly prime, because it can be changed into another prime (100244043331787) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50122021665993 + 50122021665994.
It is an arithmetic number, because the mean of its divisors is an integer number (50122021665994).
Almost surely, 2100244043331987 is an apocalyptic number.
100244043331987 is a deficient number, since it is larger than the sum of its proper divisors (1).
100244043331987 is an equidigital number, since it uses as much as digits as its factorization.
100244043331987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1741824, while the sum is 49.
Adding to 100244043331987 its reverse (789133340442001), we get a palindrome (889377383773988).
The spelling of 100244043331987 in words is "one hundred trillion, two hundred forty-four billion, forty-three million, three hundred thirty-one thousand, nine hundred eighty-seven".
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