Base | Representation |
---|---|
bin | 10010101011000111… |
… | …11011001110001011 |
3 | 221212200120212201112 |
4 | 21111203323032023 |
5 | 131013001244223 |
6 | 4334451240535 |
7 | 503303424542 |
oct | 112543731613 |
9 | 27780525645 |
10 | 10025415563 |
11 | 42850a4109 |
12 | 1b395a914b |
13 | c3a048877 |
14 | 6b169b159 |
15 | 3da22d778 |
hex | 2558fb38b |
10025415563 has 2 divisors, whose sum is σ = 10025415564. Its totient is φ = 10025415562.
The previous prime is 10025415539. The next prime is 10025415581. The reversal of 10025415563 is 36551452001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10025415563 is a prime.
It is not a weakly prime, because it can be changed into another prime (10025415583) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012707781 + 5012707782.
It is an arithmetic number, because the mean of its divisors is an integer number (5012707782).
Almost surely, 210025415563 is an apocalyptic number.
10025415563 is a deficient number, since it is larger than the sum of its proper divisors (1).
10025415563 is an equidigital number, since it uses as much as digits as its factorization.
10025415563 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 10025415563 its reverse (36551452001), we get a palindrome (46576867564).
The spelling of 10025415563 in words is "ten billion, twenty-five million, four hundred fifteen thousand, five hundred sixty-three".
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