Base | Representation |
---|---|
bin | 10010101011001000… |
… | …00010000001101001 |
3 | 221212200122021221202 |
4 | 21111210002001221 |
5 | 131013003142213 |
6 | 4334452013545 |
7 | 503303602025 |
oct | 112544020151 |
9 | 27780567852 |
10 | 10025443433 |
11 | 4285113045 |
12 | 1b396012b5 |
13 | c3a058465 |
14 | 6b16a7385 |
15 | 3da236b58 |
hex | 255902069 |
10025443433 has 4 divisors (see below), whose sum is σ = 10025659860. Its totient is φ = 10025227008.
The previous prime is 10025443427. The next prime is 10025443457. The reversal of 10025443433 is 33434452001.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5632802704 + 4392640729 = 75052^2 + 66277^2 .
It is a cyclic number.
It is not a de Polignac number, because 10025443433 - 210 = 10025442409 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10025443396 and 10025443405.
It is not an unprimeable number, because it can be changed into a prime (10025443333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7460 + ... + 141797.
It is an arithmetic number, because the mean of its divisors is an integer number (2506414965).
Almost surely, 210025443433 is an apocalyptic number.
It is an amenable number.
10025443433 is a deficient number, since it is larger than the sum of its proper divisors (216427).
10025443433 is an equidigital number, since it uses as much as digits as its factorization.
10025443433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 216426.
The product of its (nonzero) digits is 17280, while the sum is 29.
Adding to 10025443433 its reverse (33434452001), we get a palindrome (43459895434).
The spelling of 10025443433 in words is "ten billion, twenty-five million, four hundred forty-three thousand, four hundred thirty-three".
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