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100301023113 = 354796102149
BaseRepresentation
bin101110101101001101…
…0000010011110001001
3100120220011001220022220
41131122122002132021
53120404030214423
6114024435004253
710150360425624
oct1353232023611
9316804056286
10100301023113
11395a0349235
1217532739689
1395c5ca8125
144bd701cdbb
15292089b9e3
hex175a682789

100301023113 has 8 divisors (see below), whose sum is σ = 133759128000. Its totient is φ = 66855133488.

The previous prime is 100301023103. The next prime is 100301023117. The reversal of 100301023113 is 311320103001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100301023113 - 212 = 100301019017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100301023092 and 100301023101.

It is not an unprimeable number, because it can be changed into a prime (100301023117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3034638 + ... + 3067511.

It is an arithmetic number, because the mean of its divisors is an integer number (16719891000).

Almost surely, 2100301023113 is an apocalyptic number.

It is an amenable number.

100301023113 is a deficient number, since it is larger than the sum of its proper divisors (33458104887).

100301023113 is an equidigital number, since it uses as much as digits as its factorization.

100301023113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6107631.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 100301023113 its reverse (311320103001), we get a palindrome (411621126114).

The spelling of 100301023113 in words is "one hundred billion, three hundred one million, twenty-three thousand, one hundred thirteen".

Divisors: 1 3 5479 16437 6102149 18306447 33433674371 100301023113