Search a number
-
+
100302012131 is a prime number
BaseRepresentation
bin101110101101001110…
…1110011111011100011
3100120220012221011000012
41131122131303323203
53120404303342011
6114024512115135
710150402015226
oct1353235637343
9316805834005
10100302012131
11395a0964302
1217532b35aab
1395c6263349
144bd71d95bd
1529209e4a8b
hex175a773ee3

100302012131 has 2 divisors, whose sum is σ = 100302012132. Its totient is φ = 100302012130.

The previous prime is 100302012113. The next prime is 100302012163. The reversal of 100302012131 is 131210203001.

Together with previous prime (100302012113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (131210203001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100302012131 - 226 = 100234903267 is a prime.

It is a super-2 number, since 2×1003020121312 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (100302012931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50151006065 + 50151006066.

It is an arithmetic number, because the mean of its divisors is an integer number (50151006066).

Almost surely, 2100302012131 is an apocalyptic number.

100302012131 is a deficient number, since it is larger than the sum of its proper divisors (1).

100302012131 is an equidigital number, since it uses as much as digits as its factorization.

100302012131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 100302012131 its reverse (131210203001), we get a palindrome (231512215132).

The spelling of 100302012131 in words is "one hundred billion, three hundred two million, twelve thousand, one hundred thirty-one".