100312100011131 has 4 divisors (see below), whose sum is σ = 133749466681512. Its totient is φ = 66874733340752.

The previous prime is 100312100011099. The next prime is 100312100011183. The reversal of 100312100011131 is 131110001213001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100312100011131 - 2⁵ = 100312100011099 is a prime.

It is a super-2 number, since 2×100312100011131² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 100312100011131.

It is not an unprimeable number, because it can be changed into a prime (100312100011031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16718683335186 + ... + 16718683335191.

It is an arithmetic number, because the mean of its divisors is an integer number (33437366670378).

Almost surely, 2^{100312100011131} is an apocalyptic number.

100312100011131 is a deficient number, since it is larger than the sum of its proper divisors (33437366670381).

100312100011131 is an equidigital number, since it uses as much as digits as its factorization.

100312100011131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33437366670380.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 100312100011131 its reverse (131110001213001), we get a palindrome (231422101224132).

The spelling of 100312100011131 in words is "one hundred trillion, three hundred twelve billion, one hundred million, eleven thousand, one hundred thirty-one".