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100312443302497 is a prime number
BaseRepresentation
bin10110110011101111001111…
…100011001011001001100001
3111011011202221122111211002021
4112303233033203023021201
5101122004340441134442
6553202522243021441
730062222600324506
oct2663571743131141
9434152848454067
10100312443302497
1129a652a5116848
12b30128236a881
1343c8565bcc72a
141aab2107a94ad
15b8e5545b7e67
hex5b3bcf8cb261

100312443302497 has 2 divisors, whose sum is σ = 100312443302498. Its totient is φ = 100312443302496.

The previous prime is 100312443302431. The next prime is 100312443302521. The reversal of 100312443302497 is 794203344213001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60225298166016 + 40087145136481 = 7760496^2 + 6331441^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100312443302497 is a prime.

It is not a weakly prime, because it can be changed into another prime (100312443300497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50156221651248 + 50156221651249.

It is an arithmetic number, because the mean of its divisors is an integer number (50156221651249).

Almost surely, 2100312443302497 is an apocalyptic number.

It is an amenable number.

100312443302497 is a deficient number, since it is larger than the sum of its proper divisors (1).

100312443302497 is an equidigital number, since it uses as much as digits as its factorization.

100312443302497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 435456, while the sum is 43.

Adding to 100312443302497 its reverse (794203344213001), we get a palindrome (894515787515498).

The spelling of 100312443302497 in words is "one hundred trillion, three hundred twelve billion, four hundred forty-three million, three hundred two thousand, four hundred ninety-seven".