10031312113 has 4 divisors (see below), whose sum is σ = 10049651440. Its totient is φ = 10012972788.

The previous prime is 10031312089. The next prime is 10031312231. The reversal of 10031312113 is 31121313001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10031312113 - 2¹³ = 10031303921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10031312513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9168843 + ... + 9169936.

It is an arithmetic number, because the mean of its divisors is an integer number (2512412860).

Almost surely, 2^10031312113 is an apocalyptic number.

It is an amenable number.

10031312113 is a deficient number, since it is larger than the sum of its proper divisors (18339327).

10031312113 is an equidigital number, since it uses as much as digits as its factorization.

10031312113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18339326.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10031312113 its reverse (31121313001), we get a palindrome (41152625114).

The spelling of 10031312113 in words is "ten billion, thirty-one million, three hundred twelve thousand, one hundred thirteen".