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10031314034 = 27716522431
BaseRepresentation
bin10010101011110100…
…11011010001110010
3221220002200112220102
421111322123101302
5131021004022114
64335221512402
7503404522340
oct112572332162
927802615812
1010031314034
114288462785
121b3b572702
13c3b3325a1
146b2394990
153da9e62de
hex255e9b472

10031314034 has 8 divisors (see below), whose sum is σ = 17196538368. Its totient is φ = 4299134580.

The previous prime is 10031314003. The next prime is 10031314057. The reversal of 10031314034 is 43041313001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×100313140342 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10031313997 and 10031314015.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 358261202 + ... + 358261229.

It is an arithmetic number, because the mean of its divisors is an integer number (2149567296).

Almost surely, 210031314034 is an apocalyptic number.

10031314034 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

10031314034 is a deficient number, since it is larger than the sum of its proper divisors (7165224334).

10031314034 is an equidigital number, since it uses as much as digits as its factorization.

10031314034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 716522440.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 10031314034 its reverse (43041313001), we get a palindrome (53072627035).

The spelling of 10031314034 in words is "ten billion, thirty-one million, three hundred fourteen thousand, thirty-four".

Divisors: 1 2 7 14 716522431 1433044862 5015657017 10031314034