100313311311121 has 4 divisors (see below), whose sum is σ = 100319397931044. Its totient is φ = 100307224691200.

The previous prime is 100313311311113. The next prime is 100313311311163. The reversal of 100313311311121 is 121113113313001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 42068390580225 + 58244920730896 = 6486015^2 + 7631836^2 .

It is a cyclic number.

It is not a de Polignac number, because 100313311311121 - 2³ = 100313311311113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100313311311092 and 100313311311101.

It is not an unprimeable number, because it can be changed into a prime (100313311341121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3043285240 + ... + 3043318201.

It is an arithmetic number, because the mean of its divisors is an integer number (25079849482761).

Almost surely, 2^{100313311311121} is an apocalyptic number.

It is an amenable number.

100313311311121 is a deficient number, since it is larger than the sum of its proper divisors (6086619923).

100313311311121 is an equidigital number, since it uses as much as digits as its factorization.

100313311311121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6086619922.

The product of its (nonzero) digits is 162, while the sum is 22.

Adding to 100313311311121 its reverse (121113113313001), we get a palindrome (221426424624122).

The spelling of 100313311311121 in words is "one hundred trillion, three hundred thirteen billion, three hundred eleven million, three hundred eleven thousand, one hundred twenty-one".