100314304113 has 4 divisors (see below), whose sum is σ = 133752405488. Its totient is φ = 66876202740.

The previous prime is 100314304091. The next prime is 100314304121. The reversal of 100314304113 is 311403413001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311403413001 = 3 ⋅103801137667.

It is not a de Polignac number, because 100314304113 - 2¹⁷ = 100314173041 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 100314304113.

It is not an unprimeable number, because it can be changed into a prime (100314304183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16719050683 + ... + 16719050688.

It is an arithmetic number, because the mean of its divisors is an integer number (33438101372).

Almost surely, 2^100314304113 is an apocalyptic number.

It is an amenable number.

100314304113 is a deficient number, since it is larger than the sum of its proper divisors (33438101375).

100314304113 is an equidigital number, since it uses as much as digits as its factorization.

100314304113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33438101374.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 100314304113 its reverse (311403413001), we get a palindrome (411717717114).

The spelling of 100314304113 in words is "one hundred billion, three hundred fourteen million, three hundred four thousand, one hundred thirteen".