1003151130001 has 4 divisors (see below), whose sum is σ = 1035510843904. Its totient is φ = 970791416100.

The previous prime is 1003151129969. The next prime is 1003151130061. The reversal of 1003151130001 is 1000311513001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1003151130001 - 2⁵ = 1003151129969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1003151130061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16179856905 + ... + 16179856966.

It is an arithmetic number, because the mean of its divisors is an integer number (258877710976).

Almost surely, 2^{1003151130001} is an apocalyptic number.

It is an amenable number.

1003151130001 is a deficient number, since it is larger than the sum of its proper divisors (32359713903).

1003151130001 is an equidigital number, since it uses as much as digits as its factorization.

1003151130001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32359713902.

The product of its (nonzero) digits is 45, while the sum is 16.

Adding to 1003151130001 its reverse (1000311513001), we get a palindrome (2003462643002).

The spelling of 1003151130001 in words is "one trillion, three billion, one hundred fifty-one million, one hundred thirty thousand, one".