1003200012131 has 4 divisors (see below), whose sum is σ = 1003205993064. Its totient is φ = 1003194031200.

The previous prime is 1003200012107. The next prime is 1003200012137. The reversal of 1003200012131 is 1312100023001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1003200012131 is a prime.

It is a super-2 number, since 2×1003200012131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1003200012137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2731385 + ... + 3076826.

It is an arithmetic number, because the mean of its divisors is an integer number (250801498266).

Almost surely, 2^{1003200012131} is an apocalyptic number.

1003200012131 is a deficient number, since it is larger than the sum of its proper divisors (5980933).

1003200012131 is an equidigital number, since it uses as much as digits as its factorization.

1003200012131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5980932.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 1003200012131 its reverse (1312100023001), we get a palindrome (2315300035132).

The spelling of 1003200012131 in words is "one trillion, three billion, two hundred million, twelve thousand, one hundred thirty-one".