1003212311131 has 4 divisors (see below), whose sum is σ = 1017342062064. Its totient is φ = 989082560200.

The previous prime is 1003212311081. The next prime is 1003212311149. The reversal of 1003212311131 is 1311132123001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1003212311131 - 2¹⁷ = 1003212180059 is a prime.

It is a super-2 number, since 2×1003212311131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1003212311099 and 1003212311108.

It is not an unprimeable number, because it can be changed into a prime (1003212111131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7064875360 + ... + 7064875501.

It is an arithmetic number, because the mean of its divisors is an integer number (254335515516).

Almost surely, 2^{1003212311131} is an apocalyptic number.

1003212311131 is a deficient number, since it is larger than the sum of its proper divisors (14129750933).

1003212311131 is an equidigital number, since it uses as much as digits as its factorization.

1003212311131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14129750932.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1003212311131 its reverse (1311132123001), we get a palindrome (2314344434132).

The spelling of 1003212311131 in words is "one trillion, three billion, two hundred twelve million, three hundred eleven thousand, one hundred thirty-one".