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100323103147 is a prime number
BaseRepresentation
bin101110101101110111…
…0010001000110101011
3100120221200121200102221
41131123232101012223
53120430203300042
6114030544134511
710151046210121
oct1353356210653
9316850550387
10100323103147
113960185a2a3
121753a007437
1395ca739237
144bd9d29911
1529227add67
hex175bb911ab

100323103147 has 2 divisors, whose sum is σ = 100323103148. Its totient is φ = 100323103146.

The previous prime is 100323103129. The next prime is 100323103157. The reversal of 100323103147 is 741301323001.

It is a strong prime.

It is an emirp because it is prime and its reverse (741301323001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100323103147 is a prime.

It is not a weakly prime, because it can be changed into another prime (100323103157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50161551573 + 50161551574.

It is an arithmetic number, because the mean of its divisors is an integer number (50161551574).

Almost surely, 2100323103147 is an apocalyptic number.

100323103147 is a deficient number, since it is larger than the sum of its proper divisors (1).

100323103147 is an equidigital number, since it uses as much as digits as its factorization.

100323103147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 100323103147 its reverse (741301323001), we get a palindrome (841624426148).

The spelling of 100323103147 in words is "one hundred billion, three hundred twenty-three million, one hundred three thousand, one hundred forty-seven".