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100332322231313 is a prime number
BaseRepresentation
bin10110110100000001110000…
…011011010001010000010001
3111011020200021001020000220002
4112310001300123101100101
5101122321043442400223
6553220011005255345
730063525322406264
oct2664016033212021
9434220231200802
10100332322231313
1129a72776272237
12b3050ab864555
1343ca3b34969c3
141aac178976cdb
15b8ed198bae28
hex5b40706d1411

100332322231313 has 2 divisors, whose sum is σ = 100332322231314. Its totient is φ = 100332322231312.

The previous prime is 100332322231069. The next prime is 100332322231331. The reversal of 100332322231313 is 313132223233001.

Together with next prime (100332322231331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92599184385409 + 7733137845904 = 9622847^2 + 2780852^2 .

It is a cyclic number.

It is not a de Polignac number, because 100332322231313 - 230 = 100331248489489 is a prime.

It is not a weakly prime, because it can be changed into another prime (100332322231333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50166161115656 + 50166161115657.

It is an arithmetic number, because the mean of its divisors is an integer number (50166161115657).

Almost surely, 2100332322231313 is an apocalyptic number.

It is an amenable number.

100332322231313 is a deficient number, since it is larger than the sum of its proper divisors (1).

100332322231313 is an equidigital number, since it uses as much as digits as its factorization.

100332322231313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11664, while the sum is 29.

Adding to 100332322231313 its reverse (313132223233001), we get a palindrome (413464545464314).

The spelling of 100332322231313 in words is "one hundred trillion, three hundred thirty-two billion, three hundred twenty-two million, two hundred thirty-one thousand, three hundred thirteen".